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Sprague Island, Florida
Sprague Island is a island located in Wakulla County, FL at N30.08771° W84.20489° (NAD83) and at an elevation of 3 ft MSL.
Feature Type: |
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Island |
Latitude: |
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N30.08771° (NAD83 datum) |
Longitude: |
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W84.20489° |
Elevation: |
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3 ft MSL |
County: |
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Wakulla County, Florida |
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USGS 24K Map: |
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USGS 24K MRC: |
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